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6p^2-2p-20=0
a = 6; b = -2; c = -20;
Δ = b2-4ac
Δ = -22-4·6·(-20)
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{484}=22$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-22}{2*6}=\frac{-20}{12} =-1+2/3 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+22}{2*6}=\frac{24}{12} =2 $
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